In the first place, we must know the pressure (bars) of thrust that we want to exert in our hydraulic circuit, to know what forces both traction and thrust will make our cylinder.

For example: 150 bars.

To calculate the cylinder thrust capacity we must know that:

We will calculate the thrust capacity of a cylinder of 30 (Rod) x60 (Inside the tube) x300 (Stroke).

Force (Kgs): 3,14(Π) x radius² (cms) x (bars) work pressure : 3,14x32x150 = 4.239 Kgs.= 4,2 tons.

With this formula, we will know the nominal force of this hydraulic cylinder that has a pushing capacity of 4.2 tons in a circuit in which the pressure operates at 150 bars.

On the other hand, if we want it, it is to know the traction pressure of this same cylinder, we must calculate the section destined for the rod.

Area: 3.14 (Π) x radius² = Surface in cm².

30mm stem area. : 3,14 x 1.5²= 7,065cm².

60mm tube area.: 3,14 x 3,0²= 28,260cm².

Now that we have the two areas of the tube and stem, we must subtract them to obtain the excess area, and get the pulling force.

Excess area: 28,260 - 7,065 = 21,195cm².

And finally, calculate the force:

Tractive force: 21,195(cm²) x (bares)150 = 3.179,25 Kgs.= 3,1 toneladas.

So we have a 30-60 / 70-300 cylinder with a pushing force of 4.2 tons and a pulling force of 3.1 tons with a pushing pressure of 150 bar